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iVinArrow [24]
3 years ago
12

I need to find the slope for these two lines if right you’ll get brainlist

Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

-10/5 for green line aka -2x

and the parallel line would be the same -2x

the equations would be

y= =2x- 6

and the other would be

y= -2x-6

(this should be right)

Kruka [31]3 years ago
3 0

Answer:

both negative 1 over two

Step-by-step explanation:

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Which equation is false?
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A student is trying to solve the system of two equations given below: Equation P: a + b = 6 Equation Q: 4a + 2b = 19 Which of th
Marrrta [24]

Answer:

-4(a + b = 6)

Step-by-step explanation:

Given

a + b = 6

4a + 2b = 19

Required

Eliminate a

Multiply the first equation by -4

-4(a + b = 6)

Add to the second equation

-4(a + b = 6) + (4a + 2b = 19)

Solve brackets

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Open bracket

-4a + 4a -4b  + 2b = -24 + 19

-4b  + 2b = -24 + 19

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From the list of given options, the option that answers the question is -4(a + b = 6)

8 0
4 years ago
Math question down below
sergiy2304 [10]
I think the answer is 17.5 years

6 0
3 years ago
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
7 0
3 years ago
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