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Sliva [168]
3 years ago
7

You deposit $2000 each year into an account earning 3% interest compounded annually. How much will you have in the account in 25

years?
Mathematics
1 answer:
kozerog [31]3 years ago
3 0

This is what I get.  Total will be 4187.56 with  Interest 2187.56.   By using the formula: To find amount : A=p (1+r/n)^n×t Where P=2000,r=3%,n=1,t=25 So plug in and solve  A=2000(1+0.03/1)^1×25   To find interest you use formula  A=p+I A=4187.56, p=2000,i= we need to find. 4187.56=2000+I 4187.56-2000=I 2187.56=i

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Verbal expression for the following numerical expression: ( 4 + 9 ) x 3
vaieri [72.5K]

Answer:

I don't know if I'm doing this 100% correctly but I would put:

four plus nine's total multiplied by 3

3 0
3 years ago
A tortoise travels 2/12 miles per hour describe two different methods to determine the number of miles it will take to walk 3 2/
suter [353]

Answer:

11/18 miles

Step-by-step explanation:

3 2/3=11/3

2/12=1/6

1/6*11/3=11/18

7 0
3 years ago
Solve the inequality -2(z + 5) + 20 7 6.
Romashka-Z-Leto [24]

Answer:

z<2

Step-by-step explanation:

-2(z + 5) + 20 > 6

Subtract 20 from each side

-2(z + 5) + 20 -20 > 6-20

-2(z + 5) > -14

Divide each side by -2 remembering  to flip the inequality

-2/ -2(z + 5) < -14/-2

z+5 < 7

Subtract 5 from each side

z+5-5 < 7-5

z<2

8 0
2 years ago
Read 2 more answers
The sum of 4 consecutive odd numbers is 1040. Find the numbers.
Gennadij [26K]

Answer:

257+259+261+263 = 1040

Step-by-step explanation:

4 0
2 years ago
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\&#10;\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}&#10;100x&=&09.0909\overline{09}\\&#10;&&9+0.0909\overline{09}\\&#10;&&9+x&#10;\end{array}\quad \implies 100x=9+x\implies 99x=9&#10;\\\\\\&#10;x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}&#10;\\\\\\&#10;\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
3 years ago
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