Step-by-step explanation:
so sorry
don't know but please mark me as brainliest please
QUESTION:- EVALUATE THE EXPRESSION
EXPRESSION:-
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20)
<h3>ANSWER-></h3>
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2} \\ {( {27 {a}^{3} {b}^{4} } )}^{ \frac{2}{6} } \\ {({27 {a}^{3} {b}^{4} } )}^{ \frac{ \cancel{2}}{ \cancel6 {}^{ \: 3} } } \\ {(27)}^{ \frac{1}{3} } {a}^{ \frac{3}{3} } {b}^{ \frac{4}{3} } \\{(3)}^{ \frac{ \cancel3}{ \cancel3} } {a}^{ \frac{ \cancel3}{ \cancel3} } {b}^{\frac{3 + 1}{3} } \\3a {b}^{ \frac{ \cancel3}{ \cancel3} } {b}^{ \frac{1}{3} }](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20%20%5C%5C%20%7B%28%20%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B2%7D%7B6%7D%20%7D%20%20%5C%5C%20%7B%28%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel%7B2%7D%7D%7B%20%5Ccancel6%20%7B%7D%5E%7B%20%5C%3A%20%203%7D%20%7D%20%7D%20%5C%5C%20%7B%2827%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B3%7D%7B3%7D%20%7D%20%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20%5C%5C%7B%283%29%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Bb%7D%5E%7B%5Cfrac%7B3%20%2B%201%7D%7B3%7D%20%7D%20%5C%5C3a%20%7Bb%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Bb%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20)
![\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }](https://tex.z-dn.net/?f=%20%5C%5C%20ANSWER-%3E3ab%20%5Csqrt%5B3%5D%7Bb%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%5C%3A%203a%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20)
Answer:
<h3>THE SCIENCE OF COLLECTING, REVIEWING AND ANALYSING DATA.</h3>
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
Fraction of strawberry = 1 / (2 + 1)
Fraction of strawberry = 1/3
Volume = πr²h/3
Volume = π(1.5)²(8)/3
Volume = 6π
Volume of strawberry = 1/3 x 6π
Volume of strawberry = 2π in³
