A common multiple of 8 and 5
2 answers:
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Answer:
ΔRMS ≅ ΔRQS by AAS
Step-by-step explanation:
See the diagram attached.
Given that ∠ RMS = ∠ RQS and N is any point on RS and ∠ MRS = ∠ SRQ.
Therefore, between Δ RMS and Δ RQS, we have
(i) ∠ RMS = ∠ RQS {Given}
(ii) ∠ MRS = ∠ SRQ {Also given} and
(iii) RS is the common side.
So, by angle-angle-side i.e. AAS criteria we can write ΔRMS ≅ ΔRQS. (Answer)
Answer:
The formula to find the nth term of the given sequence is 54 ·
Step-by-step explanation:
The formula for nth term of an geometric progression is :
In this example, we have = 36 (the first term in the sequence) and
r = (the rate in which the sequence is changing).
Knowing what the values for r and are, now we can solve.
=
= 54 ·
Therefore, the formula to find the nth term of the given sequence is
54 ·