I'll explain how to do the first one:-
y = cos-1(x2)
This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.
We need to apply the chain rule.
Personally I find this easier to understand if i let u = x^2, so
If y = f(u) and u is a function of x then
dy/dx = dy/ du * du/dx
Here u = x^2 and y = cos-1(u)
du/dx = 2x
so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx
= -1 / √(1 - u^2) * 2x
= -2x / √(1 - u^2)
= -2x / √(1 - (x^2)^2)
= -2x / √(1 - x^4)
I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.
Answer: The answer is (B)
Explanation: The answer is (B) because, there are 2 zeros so that means that there would have to be a 2 behind the 10 and then there is 2,3,4,and 9. We take out the 9 and use the other numbers, bring over the decimal and now you have 
.
Answer:
27 employees are temporary
Step-by-step explanation:
Given Information: 30 employees and 90% are temporary
To find the number of temporary employees: 30*90%=30*9/10=27
27 employees are temporary
Answer:
red
Step-by-step explanation:
Answer:
(x + 3)/(x + 1) .
Step-by-step explanation:
2x^2 + 3x/(2x + 3)(x - 2) - 6 /x^2 - x - 2
= 2x^2 + 3x/(2x + 3)(x - 2) - 6 / (x - 2)(x + 1)
The LCM is (2x + 3)(x - 2)(x + 1) so we have
(2x^2 + 3x)(x + 1) - 6(2x + 3) x( 2x + 3)(x + 1) - 6(2x + 3)
--------------------------------------- = ------------------------------------
(2x + 3)(x - 2)(x + 1) (2x + 3)(x - 2)(x + 1)
(2x + 3)(x(x + 1) - 6) (2x + 3)(x - 2)(x + 3)
= ---------------------------- = --------------------------- = (x + 3)/(x + 1)
(2x + 3)(x - 2)(x + 1) (2x + 3)(x - 2)(x + 1)
