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olga55 [171]
3 years ago
6

Solve for me pls

7B1%7D%20" id="TexFormula1" title="f(x) = x + \sqrt{x + 1 \frac{x} - {1} " alt="f(x) = x + \sqrt{x + 1 \frac{x} - {1} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Given

f(x) = x + \frac{\sqrt{x+1} }{x-1}

To evaluate f(3), substitute x = 3 into f(x) , that is

f(3) = 3 + \frac{\sqrt{3+1} }{3-1}

     = 3 + \frac{\sqrt{4} }{2}

     = 3 + \frac{2}{2}

     = 3 + 1

     = 4 → A

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Can you help with did pretty please I'm stuck help just a, c ,d thanks luv.
Misha Larkins [42]

Answer:

a) The slope of the function is 3.

c) The equation is represented by n(t) = 3\cdot t + 35.

d) The y-intercept of the function is 35.

Step-by-step explanation:

a) According to the statement, we must assume that number of pieces of mail that must be hand-sorted (dependent variable) is represented by a linear function in terms of time (independent variable). That is:

n(t) = m\cdot t + n_{o} (1)

Where:

m - Slope, measured in number of pieces per minute.

t - Time, measured in minutes.

n_{o} - Initial number of pieces of mail that must be hand-sorted (y-intercept), measured in pieces.

n - Current number of pieces of mail that must be hand-sorted, measured in pieces.

From Geometry, we know that a line can be formed by know two distinct points. If we know that n(15\,min) = 80\,p and n(45\,min) = 170\,p, then the following system of linear equations is formed:

15\cdot m + n_{o} = 80 (2)

45\cdot m + n_{o} = 170 (3)

The solution of the system of equations is:

m = 3 and n_{o} = 35

The slope of the function is 3.

c) By (1) and using results from a) we conclude that the equation function is:

n(t) = 3\cdot t + 35 (4)

d) The y-intercept of the function is 35.

5 0
3 years ago
1. When you measure the length of an object to the eighth of an inch and again to the fourth of an inch, which measurement is mo
sladkih [1.3K]

Answer:

The eighth of an inch scale measures more precisely.

Step-by-step explanation:

An eighth of an inch means that one inch is divided into 8 equal lengths on the scale i.e. the minimum length that can be measured is \frac{1}{8} =0.125 inch.

Again a fourth of an inch means that one inch is divided into 4 equal lengths on the scale i.e. the minimum length that can be measured is \frac{1}{4} =0.25 inch.

Therefore, the eighth of an inch scale measures more precisely as it can measure more small measurements. (Answer)

6 0
3 years ago
The following table shows the monthly defect rate for a product at a manufacturing company.
Lapatulllka [165]

Answer:

3

Step-by-step explanation:

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3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
X + 4y = -8 x-4y=-8 elimination
Juli2301 [7.4K]

Steps :-

■ Eliminate the equations (subtract them). You'll get the value of 1 variable.

■ Then substitute in another equation to get the value of the other variable.

Answer :-

■ x = -8 & y = 0

See the attachment for the steps.

________

Hope it helps ⚜

6 0
3 years ago
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