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Mekhanik [1.2K]
4 years ago
5

F(x) = -3(x + 2)2 + 10 in standard form

Mathematics
1 answer:
ANEK [815]4 years ago
4 0
Nothing can be done to make it into standard form
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Let x represent the number of small candle. let y represent the number the number of large candles.
Maru [420]

Answer:

The inequality that models the situation is 2.25x+4.75y \leq 80

Step-by-step explanation:

Let

x ----> represent the number of small candles

y ----> represent the number of large candles

we know that

The inequality that represent this situation is equal to

2.25x+4.75y \leq 80

using a graphing tool

The solution is the shaded triangular area, because the number of candles cannot be a negative number

see the attached figure

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4 years ago
Jeremy and Cerardo run at constant speeds. Let x = time and y= distance. Assuming they run the same path, when will Jeremy catch
bixtya [17]
Notice that the 2 graphs intersect when x = 12 minutes.  That's your answer.
6 0
3 years ago
Describe how the unit cost changes as the quantity of sugar increases. show work
Otrada [13]
The unit cost decreases the more you buy at once. 1.10/1 = $1.10 you're paying $1.10 per 1. 1.98/2 = $ .99 you're paying $.99 per 1 2.89/3 = $.96 you're paying $.96 per 1. When you buy 9 you're paying less per 1 than you are when you buy 1
7 0
4 years ago
Please help me! And get marked as brainlist!
Luda [366]

Answer:

Step-by-step explanation:

a) area of the rectangle = length × breadth

Therefore area should be = 12cm × 6cm

Which should give you the answer 72centimetre squared.

b) area of triangle A = 1/2 × b × h

So that is 1/2 × 3 × 6

Which is 18 centimetres × 1/2

Which is 9 centimetres squared

c) area of triangle B = 1/2 × b × h

So 1/2×3×6=18

Now 1/2×18 should give you 9 centimetres squared

d) therefore the area of the parallelogram = 72+9+9=90 centimetres squared

Therefore the area of the parallelogram is 90 centimetres squared

8 0
3 years ago
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dusya [7]

Answer:

I think the way they are telling is that the triangle will move to the third quadrant,

If so, then the coordinates of P'Q'R' will just be the negative of PQR.

5 0
3 years ago
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