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Lena [83]
3 years ago
13

Simplify 7(2x+y)+6(×+5y)

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0

Simplify, <em>7(2x+y)+6(x+5y).</em>

<em>a:</em> <em>20x+37y</em>

<em> (7 • (2x + y)) +  6 • (x + 5y) </em>

<em>Step  2  : </em>

<em>Equation at the end of step  2  : </em>

<em>  7 • (2x + y) +  6 • (x + 5y) </em>

<em>Step  3  : </em>

<em>Final result : </em>

<h3><em> </em><em> 20x + 37y</em></h3>

Thanks,

<em>Deku ❤</em>

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Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2
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\bold{[ \ Answer \ ]}

\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}

\bold{[ \ Explanation \ ]}

  • \bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}

\bold{-------------------}

  • \bold{Rewrite}

\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Rewrite}

\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}

\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}

  • \bold{Rewrite}

\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}

  • \bold{Simplify}

\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}

\boxed{\bold{[] \ Eclipsed \ []}}

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Apply pythagorean theorem to find AB:

Thus:

AB = √(11.9² + 10²)

AB = √241.61

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Step-by-step explanation:

Step 1:

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