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2 years ago

Phil ran 4 3/8 miles yesterday. Michael ran 1 5/8 miles yesterday. How much farther did phil run than Michael

Mathematics

1 answer:

djyliett [7]2 years ago

8 0

Phil ran 2 7/8 miles more than micheal

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Points A, B, C, and D are collinear and positioned in that order. Find the length indicated 7) Find BC if BC = 2x + 4, AD = 28,

belka [17]

Answer:

7) BC = 10

8) BD = 20

Step-by-step explanation:

7) The segment addition theorem tells you ...

AB +BC +CD = AD

(3x+2) +(2x+4) +(3x-2) = 28

8x +4 = 28 . . . . collect terms

8x = 24 . . . . . . . subtract 4

x = 3 . . . . . . . . . divide by 8

BC = 2x+4 = 2(3) +4

BC = 10

8) AB +BD = AC +CD

(2x -14) +(-7 +3x) = (2x -3) +(9)

5x -21 = 2x +6

3x = 27

x = 9

BD = -7 +3x = -7 +3(9)

BD = 20

7 0

3 years ago

Solve the quadratic equation x2+8x−30=0 by completing the square.

diamong [38]

Answer:

$\bold{x=-4\pm\sqrt{46}}$

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\\\\\\x^2+8x-30=0\\\\\underbrace{x^2+2\cdot x\cdot 4+4^2}-4^2-30=0\\\\{}\qquad(x+4)^2\,-\,16-30=0\\\\{}\qquad\ \ (x+4)^2=46\\\\ {}\qquad\ \ x+4=\pm\sqrt{46}\\\\ {}\qquad\ \ x=-4\pm\sqrt{46}$

5 0

2 years ago

How do you divide 15 pounds of rice into 4 unequal measuring using ounces

Helen [10]

You have to cut 15 pounds into 3.75 four times

7 0

3 years ago

Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

3 0

2 years ago

2(x+3)=x-4<br> please help me <3

vovikov84 [41]

2(x + 3) = x - 4

distribute

2x + 6 = x - 4

either subtract 6 from both sides or add 4. i will be subtracting 6.

2x = x - 10

subtract x from both sides

x = -10

4 0

2 years ago