Answer:
I added a picture, with the answers. I hope it’s good.
Step-by-step explanation:
(03.01) The domain of the following relation R {(6, −2), (1, 2), (−3, −4), (−3, 2)} is 1 {−3, −3, 1, 6} 2 {−4, −2, 2, 2}
1 answer:
You might be interested in
Answer:
C
Step-by-step explanation:
The multiples of 3 are
3, 6, 9, 12, 15, ...........
The terms form an arithmetic sequence with common difference of 3.
The sum to n terms is
=
[2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = 3 and d = 3, thus
=
[ (2 × 3) + (139 × 3) ]
= 70(6 + 417) ] = 70 × 423 = 29610 → C
Answer:
Step-by-step explanation:
We are looking for what number times .50 makes the equation true.
So, just do backwards equation:
Thus, meaning that what multiplied by 0.50 is equal to 17?
[tex]0.50 * 34[tex]
[tex]==> 17[tex]