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Natasha2012 [34]
3 years ago
15

Help immediately!!!!! What is the average rate

Mathematics
2 answers:
Snezhnost [94]3 years ago
6 0

Answer:

the average rate of change is 4

Step-by-step explanation:

Akimi4 [234]3 years ago
4 0

Answer:

4

Step-by-step explanation:

1. Information

Another word for the average rate of change is the slope. The question is essentially asking, what the slope is over the interval of [3, 4]. Hence, one will use the following points, that are on this given function;

(3, -5), (4, -1)

One must also know that the formula for slope is;

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

2. Solving

Input the given points into the formula and solve.

\frac{(-1)-(-5)}{(4)-(3)}

\frac{-1+5}{1}

\frac{4}{1}

4

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Answer:

  • Jacob: 4
  • his mother: 39

Step-by-step explanation:

Let J and M represent the current ages of Jacob and his Mother.

<u>currently</u>:

  M = 3 +9J

<u>in 11 years</u>:

  M+11 = 5 +3(J+11)

Using the first equation to substitute for M in the second, we have ...

  (3 +9J) +11 = 5 +3(J +11) . . . . . substitute for M

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Jacob is 4 and his mother is 39.

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Find the value of the expression below for x=10<br><br> x ^2 - 2 (x + 5)
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Step-by-step explanation:

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
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Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

3 0
3 years ago
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