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jolli1 [7]
3 years ago
12

What is 200 divided by 150

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0
It is 1.3 because there is a remainder
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Can someone help me on this problem
Svetradugi [14.3K]
1.5p+3p+2.5p= total amount
5 0
3 years ago
Read 2 more answers
If x^2 + 2= 3^2/3+3^-2/3 then prove that 3x^2+ 9x - 8 = 0.
Karo-lina-s [1.5K]
Lol i’m not 100% sure but i’m am guessing 103 because it would be simplified
5 0
3 years ago
The quadratic equation whose roots are 1/2 and - 1/2 is<br>​
lesya692 [45]

Answer:

4x^2 - 1 = 0

Step-by-step explanation:

x = 1/2, x = -1/2

2x = 1, 2x = - 1

2x - 1 = 0, 2x + 1 = 0

( 2x - 1 )( 2x + 1 ) = 0

4x^2 - 1 = 0

6 0
3 years ago
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
2 years ago
Toying with Spacetime Consider the two dimensional vector space R2, endowed with an inner product given by (v.w) = -20W + vw1 fo
7nadin3 [17]

Answer:

See all workings below.

Step-by-step explanation:

6 0
3 years ago
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