Let w = washer and d = dryer:
w + d = $770,
but w = d + 70, replace w with d+70
(d+70) + d = 770
2d + 70 =770
2d = 770 -70 = 700
and d=$350, then w=350+70 = 420
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
Step-by-step explanation:
hello :
if : r the radius ( r ≠0)
the circumference is : 2πr
the area is : πr²
so : πr² = 2πr
simplify by : r π you have : r=2
