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3 years ago

I need help on number 8 please

Mathematics

1 answer:

belka [17]3 years ago

8 0

Well, the area of a trapezoid is A = ( $b_{1}$ + $b_{2}$ ) * h * 1/2 so you can use the area of a parallelogram, which is A = l * w, by splitting the trapezoid into 2 triangles and one rectangle. So you'd use A = l * w for the rectangle and A = 1/2bh for the triangles. You'd get the same answer!

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Write an equivalent expression to 3 2/3 times 8 3 ^4

Alexxandr [17]

Answer:

hope this helps

Step-by-step explanation:

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3 years ago

Which of the following theorems verifies that ABC ~ STU?

Lunna [17]

Answer:

B. AA

Step-by-step explanation:

The diagram given shows that two angles in ∆ABC are congruent to two corresponding angles in ∆STU.

Invariably, the third unknown angle of both triangles would also be equal going by the third angle theorem.

Thus, based on the AA Similarity Theorem which says that two triangles are similar to each other if two corresponding angles of one is congruent to two angles in the other, ∆ABC ~ ∆STU.

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3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

4 0

3 years ago

Vertices (15,0) and (-15,0), conjugate axis of length 4 units

algol [13]

Answer:

Step-by-step explanation:

16 units

8 0

3 years ago

On a coordinate plane, a line goes from point (negative 3, negative 2) to (2, 4). The distance between the two points pictured i

Mnenie [13.5K]

Answer:

n =

Step-by-step explanation:

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Now we use the distance formula replacing the general coordinates by the given values as follows:

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7 0

3 years ago

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