Does anyone want to do my apex homework ?
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Absolute value cannot be less than 0
Solve Absolute Value.<span><span>|<span>x−5</span>|</span>=<span>−1</span></span>No solutions.
<span>|<span><span>−6</span>−<span>2x</span></span>|</span>=8
<span>x=<span>−<span><span>7<span> or </span></span>x</span></span></span>=<span>1
</span>
<span>|<span><span>5x</span>+10</span>|</span>=10
<span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−4</span>
<span>|<span><span>−<span>6x</span></span>+3</span>|</span>=<span>0
</span>
So your answer is D) |–6x + 3| = 0
Solve Absolute Value.<span><span>|<span>x−5</span>|</span>=<span>−1</span></span>No solutions.
<span>|<span><span>−6</span>−<span>2x</span></span>|</span>=8
<span>x=<span>−<span><span>7<span> or </span></span>x</span></span></span>=<span>1
</span>
<span>|<span><span>5x</span>+10</span>|</span>=10
<span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−4</span>
<span>|<span><span>−<span>6x</span></span>+3</span>|</span>=<span>0
</span>
So your answer is D) |–6x + 3| = 0
The 1st, 2nd, and 3rd sides of the triangle are 16, 20, and 8 respectively.
Given that the perimeter of the triangle is 44 cm.
Let us consider a side 's' which is 4 cm shorter than the second side.
That means the second side is 4 cm longer than s, hence the second side is s+4 cm in length.
We also have that the side of length s is of length twice as long as the third side.
Hence, the length of the third side is half that of s so, it is of length s/2.
Hence, at the end 44=s+(s+4)+(s/2)=s(2+1/2)+4
⇒ s(5/2)=40
⇒ s=8*2=16
So, the 1st, 2nd, and 3rd sides of the triangle are 16, 20, and 8 respectively.
Learn more about triangles here-
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