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3 years ago

Identify the domain of y = 3/x + 2).

Mathematics

1 answer:

lions [1.4K]3 years ago

8 0

Answer:

(−∞,0) (0,∞)

Step-by-step explanation:

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If f(x) = х2 – 2х + 3, thеn find<br> f(-3).

exis [7]

Answer:

$\huge\boxed{\sf f(-3) = 18}$

Step-by-step explanation:

$\sf f(x) = x^2 - 2x + 3$

$\sf f(-3) = (-3)^2 -2(-3) + 3\\f(-3) = 9 + 6 + 3\\f(-3) = 18$

3 0

3 years ago

Given f(x)=x^2-4x+5, what's the value when f(2)

Reil [10]

If you were to replace the x's with 2, your equation would turn into:

(2)^2-4(2)+5

From there, you'd just solve.

4-8+5=1

Your answer would be 1.

7 0

3 years ago

By what percent will a fraction decrease if its numerator is decreased by 85% and its denominator is decreased by 25%??

belka [17]

Answer:

106.67%

Step-by-step explanation:

85% as a fraction is 4/5

25% as a fraction is 3/4

Convert 16/15 to a decimal: 1.067

Multiply: 1.067 · 100= 106.67%

4 0

3 years ago

Plz plz plz I need 546463+54543 times 64 it’s due in 4 min

Airida [17]

Woah! Those are some big numbers! Anyways heres my answer: I used the old school way of fuigreing this out but using the pencil and paper I fuigred out 546463+54543 is equal to 601006 and if you were to multiply this by 64 (it took a LONG time for me and quite a few mess ups) its 38464384. Though I gave you the answer I'm just wondering if you could use a calculator because it would be a whole lot easier if you were able to do so.

4 0

2 years ago

What are all values of x for which the series shown converges?

adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

$\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}$

We can write this as:

$\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}$

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

$\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}$

Then we have the inequality

$1 > (x - 2)/3$

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0

2 years ago