Indentity property, anything times 1= the same number so the answer is (p) times 6
then associative property of mult
note:a(b)=a times b and =ab
a(bc)=(ab)c
so (p)6=(p6)=6p
Answer:
5m^4n^3
15m^2n^2
Step-by-step explanation:
Given :GCF is ![5m^2n^2](https://tex.z-dn.net/?f=5m%5E2n%5E2)
m^5 n^5 : there is no 5 so GCF is not 5m^2n^2
5m^4n^3: GCF m^2, exponent 2 is less than exponent 4 . also GCf n^2 , exponent 2 is less than exponent 3. So GCf is 5m^2 n^2
10m^4n: GCF n^2 , exponent 2 is greater than exponent 1. so it does not have GCF
15m^2n^2 : 15 is 3*5 . so it has GCf is 5 m^2n^2
24m^3n^4: 24 is 3*2*2*2 . it does not have 5 . so GCF is not 5m^2n^2
Answer:
i do not understand it is not clear to me
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer = x=-2
Answer:![\frac{1}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B15%7D)
Step-by-step explanation:
Given
There are
4 country music CD
1 rock and roll CD
2 rap CD
3 Tejano CD
![\text{Probability that Jerry randomly select a Tejano CD and then a rap CD from his case}=\text{Probability of selecting a Tejano CD}\times \text{Probability of selecting a rap CD}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20that%20Jerry%20randomly%20select%20a%20Tejano%20CD%20and%20then%20a%20rap%20CD%20from%20his%20case%7D%3D%5Ctext%7BProbability%20of%20selecting%20a%20Tejano%20CD%7D%5Ctimes%20%5Ctext%7BProbability%20of%20selecting%20a%20rap%20CD%7D)
![P=\frac{3}{10}\times \frac{2}{9}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B3%7D%7B10%7D%5Ctimes%20%5Cfrac%7B2%7D%7B9%7D)
![P=\frac{2}{30}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B2%7D%7B30%7D)
![P=\frac{1}{15}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B15%7D)