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<u>Answer:</u>
The point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of is 4x + y -25 = 0
<u>Solution:</u>
The point slope form of the line that passes through the points and perpendicular to the line with a slope of “m” is given as
---- eqn 1
Where “m” is the slope of the line. are the points that passes through the line.
From question, given that slope “m” =
Given that the line passes through the points (5,5).Hence we get
By substituting the values in eqn 1 , we get the point slope form of the line which is perpendicular to the line having slope can be found out.
y - 5 = -4(x - 5)
y - 5 = -4x + 20
on simplifying the above equation, we get
y - 5 + 4x -20 = 0
4x + y - 25 = 0
hence the point slope form of given line is 4x + y - 25 = 0