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frosja888 [35]
3 years ago
12

The writing with me trying in pencil and the question is find the measure of each angle indicated

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

Again every triangle is 180° and so is every straight line, so 180-105 is 75° so 75°+85° is 160 and 180-160 is 20° so your missing angle is 20°

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2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

5 0
3 years ago
Which data set has the widest spread? A. data set A: 1, 1, 2, 1, 2, 1 B. data set B: 2, 2, 4, 4, 3, 3 C. data set C: 1, 1, 2, 2,
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Shelly biked 21 miles in 4 hours. What is Shelly average speed in miles per hour
Maksim231197 [3]
To solve this, you would divide the miles by the number of hours, 21 / 4
21 divided by 4 equals 5.25
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3 years ago
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
HELP PLEASE MATH!! A company is testing tires for wear and tear. A given tire is said to either pass the test (P) or fail the te
Xelga [282]

Answer:

  PPF, PFF

Step-by-step explanation:

There are several ways you can list all the possible combinations. A couple of my favorite are a) use a binary counting sequence; b) use a gray code counting sequence.

Using the first method, the binary numbers 000 to 111 can be listed in numerical order as 000, <em>001</em>, 010, <em>011</em>, 100, 101, 110, 111. Letting 0=P and 1=F, the ones missing from your list are the ones in italics in my list.

Using the second method, we change the right-most character, then the middle one, and finally the left-most character so there is one change at a time: 000, <em>001</em>, <em>011</em>, 010, 110, 111, 101, 100.

After you have a list of all possible combinations, it is a simple matter to compare the given list to the list of possibilities to see which are missing.

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