Answer:
20/3 ounces of water is added.
Step-by-step explanation:
how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
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The acid is 40% of 20 ounces = 8 ounces.
0.4*20 = 8
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That same 8 ounces is to be 30%. The water will be the other 70%.
8/30 = x/100
30x = 800
x = 80/3, the total amount of the solution.
We started with 20, so 80/3 - 20 = 20/3
20/3 ounces of water is added.
Answer: I’m pretty sure it’s c also
Answer:
X=15
Step-by-step explanation:
A +B + C = 180
2x +4x+ 6x = 180
12x =180
X= 15
X + 2(x - 4) = 62
x + 2x - 8 = 62
3x - 8 = 62
3x = 70
x = 23 1/3 cm
Answer:
find the inverse
exchange x for y and y for x
y=2x
then
x=2y---------> clear y
y=x/2
f−1(x)=x/2
for x=32
f−1(32)=32/2----------> 16
the answer is 16
