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3 years ago

Find 14÷12 . Write your answer as a fraction in simplest form.

Mathematics

1 answer:

sleet_krkn [62]3 years ago

5 0

14/12 is 1.166666666666667 as in a fraction its 7/6

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A sociologist surveyed 300 people about their level of anxiety on a scale of 1 to 100. Unfortunately, the person inputting the d

tiny-mole [99]

Answer:

sampling error i think

Step-by-step explanation:

4 0

3 years ago

Miriam took a survey, asking each family in her neighborhood how many pets they have. She made a graph showing the results: [asy

otez555 [7]

Answer:

1.8

Step-by-step explanation:

The graph of the problem is plotted using Asymptote and attached.

From the graph:

6 Families had 0 Pets
3 Families had 1 Pets
3 Families had 2 Pets
6 Families had 3 Pets
1 Family had 4 Pets
1 Family had 5 Pets

There are a total of 20 families.

Average Number of Pets

$=\dfrac{6*0+3*1+3*2+6*3+1*4+1*5}{20} \\\\=\dfrac{36}{20}\\\\=1.8$

The average number of pets per family is 1.8.

4 0

3 years ago

A trapezoid is broken into a triangle and rectangle. The rectangle has a base of 10 centimeters and a height of 12 centimeters.

masya89 [10]

Answer:

area of rectangle = 120 cm²

area of triangle = 24 cm²

area of trapezoid = 144 cm²

Step-by-step explanation:

12 * 10 = 120

12 * 4 = 48

48 / 2

add the triangle and rectangle area together

6 0

3 years ago

Read 2 more answers

Carla uses a compass and straightedge to construct perpendicular lines. Daryl uses technology to construct perpendicular lines.

devlian [24]

They can be different because Daryl is doing it online so he will not have to swing arcs on the computer screen he will just use circles. Hope that this helps!

∪⊂⊃⊆⊇∩

6 0

3 years ago

A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confi

USPshnik [31]

Answer:

The significance level for this case would be $\alpha=1-0.95=0.05$ and the critical value for this case would be:

$z_{\alpha/2}=1.96$

The margin of error is given by:

$ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing we got:

$ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683$

And the margin of error for this case would be $ME = 0.07$

Step-by-step explanation:

For this case we have the following dataset given:

$n= 146$ represent the sample size

$\hat p =0.23$ represent the estimated proportion of interest

$Conf=0.95$ represent the confidence level

The significance level for this case would be $\alpha=1-0.95=0.05$ and the critical value for this case would be:

$z_{\alpha/2}=1.96$

The margin of error is given by:

$ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing we got:

$ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683$

And the margin of error for this case would be $ME = 0.07$

4 0

3 years ago