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KATRIN_1 [288]
3 years ago
13

The slope of the line that contains the points (1, -1) and (2, 3) is 4. What is the y-intercept?

Mathematics
1 answer:
MrRissso [65]3 years ago
4 0
Y- intercept =-5
y-y1=m(x-x1)
y-(-1)=4(x-1)
y+1=4(x-1)
y+1=4x-4
y=4x-4-1
y=4x-5
Or
y=4x+b
-1=4(1)+b
-1=4+b
-1-4=b
-5=b. Y-intercept is -5
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Need help worth 34 points!
exis [7]
  x + y = 3
- x        - x
        y = -x + 3

  y - y₁ = m(x - x₁)
y - (-1) = -1[x - (-1)]
  y + 1 = -1(x + 1)
  y + 1 = -1(x) - 1(1)
  y + 1 = -x - 1
     - 1         - 1
       y = -x - 2

The answer is B.
6 0
3 years ago
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SOMEONE HELP ME WITH THIS
Alexandra [31]

Answer:

X=7 and y=6

Step-by-step explanation:

Y=-2x + 20.......eq(i)

6x-5y=12.....eq(ii)

Now, putting y= - 2x +20 in eq (ii)

6x - 5(-2x + 20)=12

6x + 10x - 100 = 12

16x=12+100

X=112 /16

X=7

Then, putting x=7 in eq (i)

Y=-2*7 +20

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8 0
3 years ago
A surveyor find that the cross section of the bottom of a circular pound has the shape of a parabola. The pond is 24 feet in dia
Rzqust [24]

Answer:

I wanna say 48 squared feet

Step-by-step explanation:

4 0
3 years ago
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11. Which of the following points is on the
Alona [7]

a

Step-by-step explanation:

because it's is very important

7 0
3 years ago
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Giving brainliest and max rating.
Yanka [14]

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

Cost of one ticket = $5

Cost of x tickets = $5x

So, total cost is

y=5x

The required equation is y=5x.

At x=1,

y=5(1)

y=5

At x=2,

y=5(2)

y=10

At x=3,

y=5(3)

y=15

The required table of values is

x       y

1        5

2      10

3      15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are y=5x, table A, graph B, therefore the correct option is B.

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