Answer:
5.79 feet
Step-by-step explanation:
Let us represent
First piece = x
Second piece = y
Third piece = z
Sac had a rope that was 15 feet long.
x + y + z = 15
He cut it into three pieces.
The first piece was 3.57 feet longer than the second piece.
x = 3.57 + y
The third piece was 2.97 feet longer than the second piece.
z = 2.97 + y
How long was the third piece of rope?
x + y + z = 15
3.57 + y + y + 2.97 + y = 15
3y + 6.54 = 15
3y = 15 - 6.54
3y = 8.46
y = 8.46/3
y = 2.82 feet
Therefore, the length of the third piece z = 2.97 + y
z = 2.82 + 2.97
z = 5.79 feet
Answer:
Correct option:
"z requires that you know the population standard deviation σ which may be unrealistic."
Step-by-step explanation:
The hypothesis test for significant population mean <em>μ</em> can be done either using the <em>z</em>-distribution of <em>t</em>-distribution.
Both the distribution require certain conditions to be fulfilled to use.
For using a <em>z</em>-distribution to perform a hypothesis test for <em>μ</em> the conditions to fulfilled are:
- Population is Normally distributed.
- The population standard deviation is known.
- The sample selected is large.
For using a <em>t</em>-distribution to perform a hypothesis test for <em>μ</em> the conditions to fulfilled are:
- Population is Normally distributed.
- The sample selected is randomly selected.
If the population standard deviation is not known and we have to compute the sample standard deviation then use the <em>t</em>-distribution to perform the test for population mean.
Thus, the correct option is:
"z requires that you know the population standard deviation σ which may be unrealistic."
The question asks for the value of

where

.
First let's look at what that surface looks like.
Letting

yields

<span>Letting

yields

</span><span>Letting

yields

</span>
Therefore

is the area of the triangle defined by the three points

.
We can thus reformulate the integral as

.
By definition on the plane

thus <span>

</span>
![I=\int_{z=0}^6\left[2x+\frac{x^2}6-\frac{zx}3\right]_{x=0}^{6-z}dz=\int_{z=0}^62(6-z)+\frac{(6-z)^2}6-\frac{z(6-z)}3\right]dz](https://tex.z-dn.net/?f=I%3D%5Cint_%7Bz%3D0%7D%5E6%5Cleft%5B2x%2B%5Cfrac%7Bx%5E2%7D6-%5Cfrac%7Bzx%7D3%5Cright%5D_%7Bx%3D0%7D%5E%7B6-z%7Ddz%3D%5Cint_%7Bz%3D0%7D%5E62%286-z%29%2B%5Cfrac%7B%286-z%29%5E2%7D6-%5Cfrac%7Bz%286-z%29%7D3%5Cright%5Ddz)
<span>
![I=\int_{z=0}^6\frac{z^2}2-6z+18=\left[\frac{z^ 3}6-3z^2+18z\right]_{z=0}^6=36-108+108](https://tex.z-dn.net/?f=I%3D%5Cint_%7Bz%3D0%7D%5E6%5Cfrac%7Bz%5E2%7D2-6z%2B18%3D%5Cleft%5B%5Cfrac%7Bz%5E%203%7D6-3z%5E2%2B18z%5Cright%5D_%7Bz%3D0%7D%5E6%3D36-108%2B108)
</span>
Hence

<span>
</span>
Answer:
-11.5
Step-by-step explanation:
I just did it on the calculator :)