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marta [7]
3 years ago
5

Find the arc length????????

Mathematics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

don't believe the other guy he is a scaming bot don't click the link

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Henry was building a tent and had four spikes that he had to pound into the ground. The net of one of the spikes is shown. What
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It is exactly 4008 and thats why people love you have a nice day ^-^
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4 years ago
3500 calories for 6 servings of pie ________ calories per serving is what?
OleMash [197]

Answer:

583 rounded to the nearest whole number

Step-by-step explanation:

other wise 583.3333333333333333333333333333

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2 years ago
How can you compare seven tenths and one half without using a model
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Hi ok make a diagram that goes horzontaly and make 9 lines to get 10 squares then make another diagram that is equal to the other one and draw one lune in the middle shade in 7/10 on the first one then shade in 1/2 in the second one
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3 years ago
An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact
SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y  = 2 * x³ * y,

18xy = 2 * 3 * 3 * x * y,

− 10x²y = 2 * - 5 * x² * y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 * - 5 * 3 * 3 * y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

2y\left(x^3+9x-5x^2-45\right) - Factor out " (x^3+9x-5x^2-45\right)) " by grouping,

\left(x^3-5x^2\right)+\left(9x-45\right) - Factor 9 from 9x - 45 and x² from x³ - 5x²,

9\left(x-5\right)+x^2\left(x-5\right) - Factor out common term x - 5,

\left(x-5\right)\left(x^2+9\right) - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0
4 years ago
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