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3 years ago

PLEASE I NEED HELP NOW I WILL GIVE BRAINLIEST

Mathematics

1 answer:

My name is Ann [436]3 years ago

6 0

Answer is
A. 3 pages are edited every 5 min

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Can irrational numbers also be integers/ True or False

creativ13 [48]

Answer:

true

Step-by-step explanation:

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3 years ago

At the end of the sale, 22 crossbody purses were sold at $15 each, 34 wristlets priced at $12 were sold, 96 satchels marked at $

Brrunno [24]

Answer:

Average: 26.223529411764706 (Please round to the place value necessary since it does not say in the question.)

Step-by-step explanation:

We first find the number of items sold: 170

Then we find the total cost: 4458

We then divide 4458 by 170

We end up with the answer 26.223529411764706. (Please round to the place value necessary since it does not say in the question.)

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2 years ago

Joe has one book each for algebra, geometry, history, psychology, Spanish, English and Physics in his locker. How many different

Alisiya [41]

Answer:

There are 35 different sets of 3 books Joe could choose

Step-by-step explanation:

* Lets explain how to solve the problem

- Combination is a collection of the objects where the order doesn't

matter

- The formula for the number of possible combinations of r objects from

a set of n objects is nCr = n!/r!(n-r)!

- n! = n(n - 1)(n - 2)................. × 1

Lets solve the problem

- Joe has one book each for algebra, geometry, history, psychology,

Spanish, English and Physics in his locker

∴ He has seven books in the locker

- He wants to chose three of them

∵ The order is not important when he chose the books

∴ We will use the combination nCr to find how many different sets

of three books he can choose

- The total number of books is 7

∴ n = 7

∵ He chooses 3 of them

∴ r = 3

∵ 7C3 = 7!/3!(7 - 3)! = 7!/3!(4!)

∴ $7C3=\frac{(7)(6)(5)(4)(3)(2)(1)}{[(3)(2)(1)][(4)(3)(2)(1)]}=35$

∴ 7C3 = 35

* There are 35 different sets of 3 books Joe could choose

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3 years ago

A group of friends decided to buy a bulk of chocolate from a candy store if some friends each want 1 half of a kilogram of choco

notsponge [240]

12 People would be able to have 1 half kilogram of chocolate.
In order to solve this problem you have to multiply 6 by 2. There are two halves in a whole. 6 times 2 is equal to 12.

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3 years ago

If n(X)=200,x)=300 and n(XUY)=400

olga_2 [115]

Answer:

${ \boxed{ \bf{formular : { \tt{n(X{ \small{U}Y) = n(X) + n(Y) - n(X{ \small{n}Y)}}}}}}} \\ n(X{ \small{n}}Y) = (200 + 300) - 400 \\ = 500 - 400 \\ { \boxed{n(X{ \small{n}}Y) = 100}} \\ \\ { \underline{ \blue{ becker \: jnr}}}$

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3 years ago

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