Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
X = 42 - 19, so A - x = 23
Answer:
A. Linear
Step-by-step explanation:
As the x value goes up by 1, the y value goes up by 3 each time
Say x=5.764---
Then 1000x=5764.764---
Then 1000x-x = 5759
So 999x = 5759
So x=5759/999
I don't see how b can be 0 in this case... what does that mean? You would never divide by 0 and live to tell about it, right?
1/6 = 4/24
3/8 = 9/24
11/24
1/3 = 8/24
5/12 = 10/24
1/6, 1/3, 3/8, 5/12, 11/24