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AVprozaik [17]
3 years ago
11

X2 – 11x + 5 = -2x Solve equation to the nearest tenth

Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

x = 5/7 -> 0.714285 which to the nearest tenth would be 0.7

Step-by-step explanation:

is it x*2 or x^2?

If it were x to the power of two, then the answer would be about x1 = 0.594875 and x2 = 8.40512

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A 3-gallon bottle of fabric softener costs $28.92. What is the price per quart?
bixtya [17]

Answer:

$2.41

Step-by-step explanation:

There are 4 quarts in a gallon. If there are 3 gallons that means there is 12 quarts (3x4=12) You then take $28.92 and divide it by 12, which will give you 2.40833333 and on and on, you round that to $2.41. I hope that helps!

8 0
3 years ago
Find the next number in the pattern: 3 5 11 6 7 5 14 8 12 ? Explain why
stepan [7]

Answer:

5–3 = 2

8–5 = 3

12–8 = 4

17–12 = 5

x-17 should be 6, hence x = 6+17 = 23.

Step-by-step explanation:

7 0
3 years ago
If 433 = 100% then what percent does 383 equal
Goryan [66]

Answer:

88.46%

Step-by-step explanation:

433 - 383 = 50

50 ÷ 433 = 0.1154

0.1154 x 100 = 11.54%

100% - 11.54% = 88.46%

<u>Check work:</u>

433 x 88.46% = 383

5 0
3 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
What is the domain of function of f(x)=-2x+4x
dem82 [27]

Answer:

Domain= x∉Real numbers

Step-by-step explanation:

4 0
3 years ago
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