10.54 cm^2. You just have to find area of the square then area of the circle. Subtract the area of the circle from the square to get the answer
Answer:triangles 20 12 28 and15 9 21
Step-by-step explanation:
The solution of the given equation represented in the task content can be determined by first evaluating the LCM and hence is; y= 27.
<h3>What is the solution of the equation as given in the task?</h3>
The given equation is; (y-5)/2=(y+6)/3.
Hence, by multiplying the equation by 6, we have;
3(y-5) = 2(y+6)
3y -15 = 2y +12
y = 27.
Hence, it follows that the value of y which is a solution to the equation is; y = 27.
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I believe the correct answer is true. According to the square root property, the solution set of x^2 = 25 is {±5}. <span>The </span>square root property<span> is one method that is used to find the solutions to a quadratic (second degree) equation. This method involves taking the </span>square roots <span>of both sides of the equation. Hope this answers the question.</span>
