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3 years ago

How far is the top of the lampost from the tip of its shadow?

Mathematics

1 answer:

astraxan [27]3 years ago

3 0

Answer:

About 14.58 ft

Step-by-step explanation:

We have an angle, the side opposite that angle, and the hypotenuse of that triangle. If you remember SOH CAH TOA, the right trig ratio for this problem is sine. In this case, $\sin{49^{\circ}=\frac{11}{x}$ . We want to solve for x, so we can multiply both sides by x to get $x\sin{49^{\circ}}=11$ and then divide both sides by $\sin{49^{\circ}}$ to get $x=\frac{11}{\sin{49^{\circ}}} \approx 14.58$

So, the top of the lamppost is about 14.58 ft from the tip of its shadow

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How do you simplify (-5x^5+14)-(11x^2+1+11x^5)

lord [1]

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Like terms also: 14-1 = 13
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3 years ago

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4 years ago

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oksian1 [2.3K]

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Step-by-step explanation:

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3 years ago

Ping's Ice Cream Palace offers a special sundae that contains over 2 kilograms of ice cream plus any number of toppings. Write a

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Let "x" represent the weight of the toppings. We know that we can have any number of toppings. This means that one may ask for no toppings at all too.

Now, we have been told that "S" is the weight of the special sundae in kilograms. This definitely included the "mandatory" 2 kilograms of ice cream. Therefore, S will be at-least equal to 2.

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3 years ago

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Inga [223]

Answer: LAST OPTION

Step-by-step explanation:

The complex numbers shown have the form:

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$d=\sqrt{a^2+b^2}$

Substitute values of each option. Then:

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2) $d=\sqrt{17^2+1^2}=\sqrt{290}$

3) $d=\sqrt{20^2+(-3)^2}=\sqrt{409}$

4) $d=\sqrt{4^2+(-1)^2}=\sqrt{17}$ (CORRECT OPTION)

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3 years ago

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