This item can be solved by the probability theorem called Bayes' theorem which states that the probability of event A occurring given event B is equal to,
P(A/B) = P(A)P(B/A) / P(B)
where P(B/A) is the probability that the test will yield positive if the person has the disease. P(A) is the probability will be present in any particular person which is equal to 0.04.
P(B) is the probability of positive result irrespective of whether the disease is present of not is calculated below.
P(B) = (0.94)x (0.04) + (0.06)(0.96) = 0.0952
Now, solving for P(A/B)
P(A/B) = (0.94)(0.04) / 0.0952 = 0.039
Thus, the answer is approximately 4%.
Bob has 8 slices of pizza and he gets 12.5 more he does this 9.5 times how many pizzas did he eat. This is all I could think of
So just you need to rationalize the denominator so multiple top and bottom by conjugate so by sqrt6 +sqrt3
8 8(sqrt6 +sqrt3) 8(sqrt6 +sqrt3)
----------------- = ------------------------------------- = ----------------------- =
sqrt6 - sqrt3 (sqrt6 -sqrt3)(sqrt6 +sqrt3) 6 -3
8(sqrt6 +sqrt3)
= -----------------------
3
hope this will help you
