Irst thought: since he needs 7 3/4 tons, and each load can carry LESS than a ton, he'll need to make MORE than 7 3/4 loads. So when you get your answer, make sure it it passes that common sense test. Next: He's got to divide the 7 3/4 ton total among all those loads, 3/4 ton at a time. So he needs to divide: 7 3/4 divided by 3/4. It will be easier to do the math if we turn 7 3/4 into an improper fraction, which will be 31/4. So we have to divide 31/4 divided by 3/4, which will give us 10, with 1/4 left over, for a total of 10 1/4 loads. BUT: the wording is that each load carries AT MOST 3/4 ton, so he may carry less than that amount in any given load(s). So he needs to do an amount GREATER THAN OR EQUAL TO 10 3/4 loads. For practical purposes, that means he has to fill his truck (at least part way) 11 different times. (Think of it as completely filled the first 10 times, and 3/4 filled on the 11th/final time.)
3/4
Step-by-step explanation:
So if you simplify 1 1/2 you get 3/4. And if you multiply 3/4 by 2/2 you will get 6/4. Subtract 3/4 from 6/4 and you get 3/4.
5/(x^2-4)+2/x=2/(x-2) if we factor the leading denominator, it is a "difference of squares" of the form (a^2-b^2) which always factors to (a-b)(a+b) so we have:
5/((x-2)(x+2))+2/x=2/(x-2), to add/subtract fractions we need a common denominator, so in this case we need a common denominator of x(x-2)(x+2) so
5(x)+2(x+2)(x-2)=2(x)(x+2), perform indicated operations...
5x+2(x^2-4)=2x(x+2)
5x+2x^2-8=2x^2+4x subtract 2x from both sides
5x-8=4x subtract 4x from both sides
x-8=0 add 8 to both sides
x=8
check...
5/(x^2-4)+2/x=2/(x-2) when x=8 so
5/(64-4)+2/8=2/(8-2)
5/60+1/4=2/6
5/60+15/60=20/60
20/60=20/60
Answer: c(a+ab)=x
Step-by-step explanation:
a(x+b)=c distribute the (a)
ax+ab=c now divide by ax by x
a+ab=c/x now multiply by c
c(a+ab)=x
