Answer:
f(x) = 1/2(4 - x)(x - 1)(x - 2)
Step-by-step explanation:
Considering zero's and a coefficient, the function is:
f(x) = a(x - 4)(x - 1)(x - 2)
Considering y-intercept:
f(0) = a(0 - 4)(0 - 1)(0 - 2)
4 = a(-4)(-1)(-2)
4 = -8a
a = -1/2
So the function is:
f(x) = -1/2(x - 4)(x - 1)(x - 2) = 1/2(4 - x)(x - 1)(x - 2)
Answer:
Mya only used the dimensions from the scale drawing of a rectangle
Step-by-step explanation:
A
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
B could be the only answer
