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Soloha48 [4]
3 years ago
10

Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th

e following box plots. Identify any values of data that may affect the statistical measures of center and spread.
(SEE ATTACHED)

Mathematics
2 answers:
Tema [17]3 years ago
4 0

Answer:

d

Step-by-step explanation:

the last one of the four

ozzi3 years ago
3 0
D
The correct answer in my opinion is D hope it’s correct
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A=4,b=-2,C=5 d=-6 , e =-1 5 ed-3cb +4ba-2ea​
Alecsey [184]

Answer:

208

Step-by-step explanation:

{ed}-{3cb}+{4ba}-{2ea} = {(-15)*(-6)} - {3*5*(-2)} + {4*(-2)*4} - {2*(-15)*4}

={90} - {15*(-2)} + {16*(-2)} - {8*(-15)}

= {90} - {-30} + {-32} - {-120}

= 90 (--)30 (+-) 32 (--) 120

= 90 + 30 - 32 + 120

= 120 - 32 + 120

= 88 + 120

= 208

3 0
2 years ago
Half of the number, n, plus eight?
3241004551 [841]
Your answer would be A.
3 0
2 years ago
Read 2 more answers
1. Which would be a more helpful for solving the system: adding the two equations or subtracting
ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

\frac{2x+1}{2y}=7\\\\

Equation 2:

\frac{6x-1}{2y}=5

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\  with\ 6\\\\12x+6=84y

Now for the second equation:

\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y

Now subtracting equation 2 from equation 1

12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y

now insert this value of y into any equation

lets insert it into equation 1

\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375

5 0
3 years ago
What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12
Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, <u>2 is our minimum and 17 is our maximum.</u>

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5

<u>The median is 12.5.</u>

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6

<u>The first quartile is 6.</u>

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15

<u>The third quartile is 15.</u>

3 0
3 years ago
Please help!
SSSSS [86.1K]

A the correct answer pa brainless po

5 0
2 years ago
Read 2 more answers
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