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Marianna [84]
3 years ago
6

Pls I Need Help Fastttt

Mathematics
2 answers:
kow [346]3 years ago
5 0
Your answer will be (a)
Musya8 [376]3 years ago
4 0

Answer:

2

Step-by-step explanation:

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What is a number that when you multiply it by 0.9 and
lora16 [44]
0.9x12=10.8,, 10.8-6.3=4.5. The number is 12
8 0
3 years ago
Please help I’ll mark you as brainliest if correct!
Luden [163]
It would be B. I took a test with this
7 0
3 years ago
The present value of an ordinary annuity of​ $350 each year for five​ years, assuming an opportunity cost of 4​ percent, is​ ___
liubo4ka [24]
We can calculate it by PVOA table.
PVOA means present value of an ordinary annuity.
PMT = $350
PMT means recurring payment.
time = 5 years and interest rate is 4%
So n = 5 and i = 4%
So we can calculate PVOA as

PVOA = PMT times (PVOA factor for n = 5 and i = 4%)
             = 350 * (4.452) (PVOA factor PVOA table)
             = 1558.2
So present value is $1558.2
4 0
4 years ago
Making Friends Online
Mkey [24]

Answer:

Step-by-step explanation:

) Do you expect the distribution of number of friends made online to be symmetric, skewed to the right, or skewed to the left?

Skewed to the left.

Symmetric

Skewed to the right.

(b) Two measures of center for this distribution are 1 friend and 5.3 friends. Which is most likely to be the mean and which is most likely to be the median?

Mean=

Median=

<h2>----------------------------------</h2>

a)

as proportion of people with 0 friends is 43% whcih is on left side and maximum ; and % decrease with increasing number of friends

skewed to the right

b)

as it is skewed to the right ; therefore mean is greater than median

mean=5.3

median=1

[since for skwewed to the right distribution :mean is always greater than median, therefore higher value should be mean which is 5.3 and lower value is median which is 1]

5 0
3 years ago
Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probabili
Gemiola [76]

Answer:

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851</em>

Step-by-step explanation:

<u>step(i)</u>:-

<em>Let 'X' be the random Normal variable</em>

<em>mean of the Population = 365.45</em>

<em>Standard deviation of the population = 4.9 cm</em>

<em>Let X₁ =  360</em>

<em></em>Z= \frac{x-mean}{S.D}= \frac{360-365.45}{4.9}<em></em>

<em>Z₁ = -1.112</em>

<em>Let X₂ =  370</em>

<em></em>Z= \frac{x-mean}{S.D}= \frac{370-365.45}{4.9}<em></em>

<em>Z₂ = 0.911</em>

<u><em>Step(ii</em></u><em>):-</em>

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm</em>

<em>                   P(x₁≤x≤x₂) =    P(z₁≤Z≤z₂) </em>

<em>                P(360 ≤X≤370)   =    P(-1.11≤Z≤0.911)</em>

<em>                                      =    P(Z≤0.911)-P(Z≤-1.11)</em>

<em>                                      =   0.5 +A(0.911) - (0.5-A(1.11)</em>

<em>                                        =    0.5 +A(0.911) - 0.5+A(1.11)</em>

<em>                                       =     A(0.911) + A(1.11)</em>

<em>                                     =    0.3186 + 0.3665</em>

<em>                                      = 0.6851</em>

<em>The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851</em>

<em></em>

<em></em>

5 0
3 years ago
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