Binomial
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n=10)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (defective/normal)3. Probability is known and remains constant throughout the trials (p=5%)4. All trials are random and independent of the others (assumed from context)The number of successes, x, is then given by

where

Substituting values, p=0.05, n=10, X=exactly 1
for X=1 (defective out of n)
P(X=1)=C(10,1)0.05^1*(1-0.05)^(10-1)
=10!/(1!9!)*0.05*0.95^9
=10*0.05*0.0630249
=0.315125 (to 6 places of decimal)
Answer:
371/999
Step-by-step explanation:
all repeating numbers like that just go over nines. Two repeating? Over 99. Four repeating? Over 9,999
The expression of all the algebra as single rational exponent are; As written below.
<h3>How to Express Exponents?</h3>
1) We want to express ⁴√x³. This can be expressed as;
x^(3/4)
2) We want to express the exponent ¹/x⁻¹. This is expressed as a single rational exponent as; x
3) We want to have the given expression as a single rational exponent. The expression is; ¹⁰√(x⁵ · x⁴ · x²)
We add the exponents to get;
¹⁰√(x¹¹) = x^(¹¹/₁₀)
4) x^(¹/₃) * x^(¹/₃) * x^(¹/₃)
We just add the exponents to get;
x¹ = x
Read more about Exponents at; brainly.com/question/11761858
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Think of it as -5+1i/2i, since 1i=i. From there, the i's could cancel out since dividing a number by itself would just equal 1. It would then be -5+1/2 which would be simplified to -4 1/2. No need to worry about those i's at all!
Answer:
Step-by-step explanation:
f(-9+h)= (-9+h)² = h²-18h+81
f(-9+h)-f(-9)=h²-18h+81 -81 because : f(-9) = (-9)² = 81
f(-9+h)-f(-9)=h²-18h
(f(-9+h)-f(-9))/h=(h²-18h)/h = h(h-18)/h =h-18
lim (f(-9+h)-f(-9))/h = lim(h-18= - 18
h→0 h→0