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MakcuM [25]
3 years ago
12

given the trinomial x^2+bx-c where both the first sign is positive and the second sign is negative, the signs of the factors wil

l be:
Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer one positive one negative

geniusboy [140]3 years ago
5 0

The signs of the factors will be different. (One will be positive and one will be negative.)

_____

Here, the "first sign" is considered to be the sign of <em>x²</em>, and the "second sign" is considered to be the sign of <em>c</em>. The above statement will be true regardless of the sign of <em>b</em>. The "signs <em>of</em> the factors" is considered to refer to the signs of the constant terms <em>in</em> the binomial factors.

For (x +p)(x -q) where <em>p</em> and <em>q</em> are both positive so the signs are as shown, the product is x² +(p-q)x -pq. That is <em>x²</em> is positive and <em>-pq</em> is negative, regardless of the relative magnitudes of <em>p</em> and <em>q</em> (thus the sign of <em>p-q</em>).

_____

If something else is meant by the terminology used, it isn't clear what the intended answer is supposed to be.

Both x² +3x -10 and x² -3x -10 have factorizations that have different signs <em>in</em> the two factors. The first is (x+5)(x-2); the second is (x+2)(x-5). The signs <em>of</em> the factors are all positive: (x+5), not -(x+5), for example.

On the other hand x² -3x +2 = (x-2)(x-1) has same signs <em>in</em> and <em>of</em> the factors. That is, by themselves, the sign of x² (first sign) and the sign of 3x (second sign) don't guarantee the signs <em>in</em> the factors are anything in particular, except that at least one sign in the factors must be negative if the first (x²) and second (3x) signs differ.

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y=-1x+2

Step-by-step explanation:

I think this is the answer because 2 is the y intercept and the x is -2 but negative would not be the slope.

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Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided
DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0
3 years ago
Please help me out!!!!!
notka56 [123]

Answer: D

Step-by-step explanation:

all possible rational zeros are the factors of the last term divided by the coefficient of the first term

so it's (±1, ±3, ±9) / (±1, ±2)

(±1, ±3, ±9) / ±1 = ±1, ±3, ±9

(±1, ±3, ±9) / ±2 = ±1/2, ±3/2, ±9/2

--> ±1, ±3, ±9, ±1/2, ±3/2, ±9/2

8 0
3 years ago
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