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MakcuM [25]
3 years ago
12

given the trinomial x^2+bx-c where both the first sign is positive and the second sign is negative, the signs of the factors wil

l be:
Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer one positive one negative

geniusboy [140]3 years ago
5 0

The signs of the factors will be different. (One will be positive and one will be negative.)

_____

Here, the "first sign" is considered to be the sign of <em>x²</em>, and the "second sign" is considered to be the sign of <em>c</em>. The above statement will be true regardless of the sign of <em>b</em>. The "signs <em>of</em> the factors" is considered to refer to the signs of the constant terms <em>in</em> the binomial factors.

For (x +p)(x -q) where <em>p</em> and <em>q</em> are both positive so the signs are as shown, the product is x² +(p-q)x -pq. That is <em>x²</em> is positive and <em>-pq</em> is negative, regardless of the relative magnitudes of <em>p</em> and <em>q</em> (thus the sign of <em>p-q</em>).

_____

If something else is meant by the terminology used, it isn't clear what the intended answer is supposed to be.

Both x² +3x -10 and x² -3x -10 have factorizations that have different signs <em>in</em> the two factors. The first is (x+5)(x-2); the second is (x+2)(x-5). The signs <em>of</em> the factors are all positive: (x+5), not -(x+5), for example.

On the other hand x² -3x +2 = (x-2)(x-1) has same signs <em>in</em> and <em>of</em> the factors. That is, by themselves, the sign of x² (first sign) and the sign of 3x (second sign) don't guarantee the signs <em>in</em> the factors are anything in particular, except that at least one sign in the factors must be negative if the first (x²) and second (3x) signs differ.

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Six more than five times a number is at least twenty-one
kakasveta [241]
Lets say the number is x so we can make an equation
If is at least 21, that means it has to be greater then or equal to it.
6+5*x>=21
You can subtract 6 from both sides
5*x>=15
Then divide both sides by 5
x>=3
You can conclude that the number is greater then or equal to 3.
6 0
3 years ago
Solve 5w + 3 = 3w + 10
OverLord2011 [107]
X=7/12
Alright so let's solve this! :)
••• Subtract 3w from both sides.
<span><span><span><span>5w</span>+3</span>−<span>3w</span></span>=<span><span><span>3w</span>+10</span>−<span>3w</span></span></span><span><span><span>2w</span>+3</span>=10
</span>••• Subtract 3 from both sides.
<span><span><span><span>2w</span>+3</span>−3</span>=<span>10−3</span></span><span><span>2w</span>=7
</span>••• Divide both sides by 2.
<span>2w/2</span>=<span>7/<span>2
</span></span>=<span>7/2
and then 7/2=3.5
</span>
5 0
3 years ago
Read 2 more answers
NEED HELP WITH
Fed [463]
Let the average profit or loss in year 2006 be x millions, 


The average profit for the 8-year period, is the total sum of the profits (or losses) of each year, divided by 8:

so we have:

\displaystyle{ \frac{3.40+2.10+x+0.60+2.10+0.20+1.30+0.75}{8}=1

\displaystyle{\frac{10.45+x}{8}=1

10.45+x=8

x=8-10.45=-2.45


Answer: the loss in 2006, was 2.45 million dollars

3 0
3 years ago
Need help on how to do. explain also please
Anuta_ua [19.1K]

to the power of..

Step-by-step explanation:

2x X 2x X 2x= 8x

6 0
3 years ago
Help needed quickly
Rudiy27

Answer: your picture isn't popping up on my screen so when it pops up ill be more than welcomed to help .

Step-by-step explanation:

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3 years ago
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