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Ymorist [56]
3 years ago
9

Helen borrowed money from her aunt to pay for college expenses. The graph below shows the amount left

Mathematics
1 answer:
enot [183]3 years ago
4 0

Answer:

y = -100x + 13000

Step-by-step explanation:

See attachment for graph

First, we need to take any corresponding values of x and y

(x_1,y_1) = (0,13000)

(x_2,y_2) = (130,0)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{0 - 13000}{130 - 0}

m = \frac{- 13000}{130}

m = -100

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 13000 = -100(x - 0)

y - 13000 = -100x

Make y the subject

y = -100x + 13000

Hence, the line equation is:

y = -100x + 13000

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Ivenika [448]
The answer is definitely B
5 0
3 years ago
SOLVE BY ELIMINATION.<br><br> x-2y=2<br> 3x+y=6
USPshnik [31]
\left \{ {{x-2y=2} \atop {3x+y=6\ |\cdot2}} \right. \\\\ \left \{ {{x-2y=2} \atop {6x+2y=12}} \right. \\+-----\\\\7x=14\ \ \ \ |:7\\x=2\\\\2-2y=2\\-2y=2-2\\-2y=0\\y=0\\\\ \left \{ {{y=0} \atop {x=2}} \right.
7 0
3 years ago
1.3.12
kondaur [170]

Answer:

<h3><em>(12, -6)</em></h3>

Step-by-step explanation:

The formula for calculating the midpoint of two coordinates is expressed as shown;

M(X, Y) = [(x1+x2)/2,  (y1+y2)/2]

Given the midpoint of ST to be ((6, -2) and one endpoint T is (0,2), according to expression above;

X = (x1+x2)/2

Y = (y1+y2)/2

From the coordinates, X = 6, Y = -2, x1 = 0 and y1 = 2, to get x2 and y2;

X = (x1+x2)/2

6 =  (0+x2)/2

cross multiply

12 = 0+x2

x2 = 12-0

x2 = 12

For 2;

Y = (y1+y2)/2

-2 =  (2+y2)/2

cross multiply

-4 = 2+y2

y2 = -4-2

y2 = -6

<em>Hence the other endpoint S(x2, y2) is (12, -6)</em>

<em></em>

3 0
3 years ago
HELP!!!!<br> 2x+y= 20<br> 3x+4y= 40
bagirrra123 [75]

Answer:

(8,4)?

Step-by-step explanation:

3 0
3 years ago
Given f(x), find g(x) and h(x) such that f(x) = g(h(x)) and neither g(x) nor h(x) is solely x.
aniked [119]

Answer:

Please look at the different answers. I wasn't 100% sure what your expression was.

Step-by-step explanation:

If you mean 2/(5x-1) then g(x) will take the fraction into account with a constant 2 for the numerator and a variable for the denominator since that is where our variable is so g(x)=2/x.

Now h(x)=5x-1 since if you plug in 5x-1 into 2/x where x is you will get our original expression.

Now if you did mean (2/5)x-1 I would take notice of where the variable is which is in (2/5)x so g(x)=x-1 where h(x)=(2/5)x since if you plug (2/5)x in place of the x in x-1 you will get the original.

Please let me know if I didn't interpret your expression correctly.

6 0
3 years ago
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