Question

Use a net to find the surface Area of the square pyramid The height of the pyramid is 9 yes and the base sides are all 2.5 yrds and its a square as a base

Answer 1

Answer:

$Area = 51.68yd^2$

Step-by-step explanation:

Given

$h = 9yd$ -- height

$a = 2.5yd$ --- base sides

Required

Determine the surface area

The net is not given. So, I will solve directly.

The surface area is calculated as:

$Area = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}$

So, we have:

$Area = 2.5^2 + 2*2.5\sqrt{\frac{2.5^2}{4} + 9^2}$

$Area = 6.25 + 5\sqrt{\frac{6.25}{4} + 81}$

$Area = 6.25 + 5\sqrt{1.5625 + 81}$

$Area = 6.25 + 5\sqrt{82.5625}$

$Area = 6.25 + 5* 9.086$

$Area = 51.68yd^2$