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svetlana [45]
3 years ago
8

Write as an algebraic expression the quotient of 30 and 5

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer:

30÷5=6.

Step-by-step explanation:

Quotient means to divide, 30÷5 is 6 since 5x6 or 6x5 is 30.

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PLEASE HELP 50 points
hoa [83]

Answer:

r > 7 (C)

Step-by-step explanation:

3r−7>14

Step 1: Add 7 to both sides.

3r−7+7>14+7

3r>21

Step 2: Divide both sides by 3.

3r

3

>

21

3

r>7

Hope this helps and makes sense!! Good luck and have a wonderful day! <33

Imagine this < as a alligater and itś eating the greater number!!

8 0
2 years ago
Read 2 more answers
A manufacturer of lawnmowers wanted to know the most important product attributes to consumers. The company's research team deve
stepladder [879]

Answer: Ordinal measurement scale

Step-by-step explanation:

In ordinal measurement scale the order of values or variables are very important. Just as in the case above, the rating from 1-3 is according to the order of it's importance.

Thanks

7 0
3 years ago
A football team lost 5 yards on each 3 plays. explain how you could use a number line to find the team's change in field positio
ollegr [7]
<span>A football team lost 5 yards on each 3 plays.
Let’s use a number line to be able to see how far in the field did they lost in 3 games.
=> 1 : 5  (1 game is to 5 yards)
=> 3 : 15 (3 games is to 15 yards )
All in all they lost 15 yards in 3 games.
pls. see attachment for more presentation.</span>



5 0
3 years ago
What the value of the numerical expression 5/8-5/12(3-1/2)+2/3?
kati45 [8]

0.25

think of P.E.M.D.A.S

3 0
3 years ago
Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.​
vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}

\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}

4 0
2 years ago
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