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rewona [7]
2 years ago
12

Which expression is equivalent to -2(-7h -

Mathematics
1 answer:
disa [49]2 years ago
3 0

Answer:

a. 20h + 8

Step-by-step explanation:

-2(-7h-4) + 6h = 14h + 8 + 6h = 20h + 8

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2 years ago
If tan e = 1.3, what is the value of cot (90° - 9)?
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Answer:

A

Step-by-step explanation:

We are given that:

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And we want to find:

\cot(90^\circ -\theta)

Remember that tangent and cotangent are co-functions. In other words, they follow the cofunction identities:

\tan(\theta)=\cot(90^\circ-\theta)\text{ and } \cot(90^\circ-\theta)=\tan(\theta)

Therefore, since tan(θ) = 1.3 and cot(90° - θ) = tan(θ), then cot(90° - θ) must also be 1.3.

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2 years ago
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2 years ago
addie wrote a check to the grocery store for $156.00. However, when she looks at her check register later that night, she sees s
Vsevolod [243]
She will have one fee which is the over draft fee for covering the check
7 0
3 years ago
Read 2 more answers
A bar graph titled Time Spent Practicing with hours on the x-axis and students on the y-axis. 3 students spent 0 to 59 minutes,
MissTica

Answer:

(a)Number of students

(b)5 Students

(c)8 Students

Step-by-step explanation:

From the supplied information

\left|\begin{array}{c|c}$Time Spent Practicing(hrs)&$Number of Students\\-------&------\\$0 to 59 minutes & 3\\$1 to 1 hours and 59 minutes&5\\$2 to 2 hours and 59 minutes&8\\$3 to 3 hours and 59 minutes&4\\$4 to 4 hours and 59 minutes&1\end{array}\right|

(a)The bars represents the number of students who practiced for that particular duration.

(b)Students who spend 3 or more hours practicing

From the above table,

Number of students who spend 3 or more hours practicing=4+1

=5 Students

According to the histogram, 5 students spend 3 or more hours practicing.

(c)Students who spend fewer than 2 hours practicing

From the above table,

Number of students who spend fewer than 2 hours practicing=3+5

=8 Students

According to the histogram, 8 students spend  fewer than 2 hours practicing.

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3 years ago
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