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r-ruslan [8.4K]
4 years ago
6

Each day of the month carl earns an allowance in cents equal to the square of that date of the month.Which is a number of cents

carl could earn in a single day
Mathematics
1 answer:
olya-2409 [2.1K]4 years ago
8 0

Given condition is : Each day of the month Carl earns an allowance in cents equal to the square of that date of the month.

This simplifies that if the date is 3rd Carl will earn 9 cents, if the date is 15th, he will earn 225 cents etc.

So, the maximum days in a month is 31. So the maximum he can earn in a day will be: 31^{2}=961

Hence, in a single day he can earn 961 cents.

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Consider the parent function f(x) = x^2 and the transformed function f(x) =- 5(x - 4)^2 – 8. Identify the
madam [21]

Given:

The parent function is

f(x)=x^2

Consider the transformed function is g(x) instead of f(x) because both functions are different.

g(x)=-5(x-4)^2-8

Step-by-step explanation:

We have,

f(x)=x^2

g(x)=-5(x-4)^2-8

It can be written as

g(x)=-5f(x-4)-8            ...(i)

The translation is defined as

g(x)=kf(x+a)+b                .... (ii)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<|k|<1, then the graph compressed vertically by factor k and if |k|>1, then the graph stretch vertically by factor k.

If k is negative, then f(x) is reflected across the x-axis to get g(x).

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (i) and (ii), we get

a=-4, f(x) shifts 4 units right.

b=-8, f(x) shifts 8 units down.

k=-5, it is negative so f(x) reflected across the x-axis.

|k|=|-5|=5>1, so f(x) stretched vertically by factor 5.

Therefore, the function f(x) reflected across the x-axis, stretched vertically by factor 5 and shifted 4 units right 8 units down to get g(x).

8 0
3 years ago
Anyone please !!!!!!
IgorLugansk [536]

Answer:

4

Step-by-step explanation:

Lets start by plugging in our (a) value

a^2 + 5a + 4

(-5)^2 + 5(-5) +4

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4 is your final answer!

5 0
3 years ago
Find three numbers such that their sum is 12, the sum of the first, twice the second, and three times the third is 31, and the s
Tpy6a [65]

Answer:

a = 3, b = -1, c = 10

Step-by-step explanation:

Let the three numbers be a, b and c.

Equation 1: a + b + c = 12

Equation 2: a + 2b + 3c = 31

Equation 3: 9b + c = 1

Equation 2 - Equation 1:

Equation 4: b + 2c = 19

Equation 3 times by the number 2

Equation 5: 18b + 2c = 2

Equation 5 - Equation 4

17b = -17

b = -1

Substitute into Equation 4:

2c - 1 = 19

2c = 20

c = 10

Substitute into Equation 1:

a + b + c = 12

a - 1 + 10 = 12

a = 3

8 0
3 years ago
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zimovet [89]

Answer:

Step-by-step explanation:

32

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Step-by-step explanation:

That is the answer sister-in-law

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