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Katen [24]
3 years ago
12

Last question I think HELP ME ITS FIXING TO BE OVER DUE!!!

Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

I am not good at this but a good app for math is Math

way

~Hope this helps!!Stay safe~

You might be interested in
14 + 21 + 16<br> Total count –<br> Mean Value
andrew-mc [135]

Answer:

34

Step-by-step explanation:

Total count= 14 + 21 + 16

= 51

Mean value = Total count / number of values

= 51/3

= 17

Hence, Total count - mean value = 51 - 17

= 34

8 0
4 years ago
Can someone please help me out? I will mark brainliest I can’t figure this out
Dafna1 [17]
The answer will be 95° but I am not sure
3 0
3 years ago
47. The legs of a triangle measure 7 mm and 24 mm. What length hypotenuse makes the triangle a right triangle?
k0ka [10]

Answer:

B

Step-by-step explanation:

according to pythagorean

7^{2} + 24^{2} =x^{2} (x>0)

=> x^{2} =625

=>x=\sqrt{625} = 25

6 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
4 years ago
Is 2(4x-8)=-20equivalent to 8x-16=-20
Nadusha1986 [10]

Answer:

yes

Step-by-step explanation:

distribute 2 on the L.H.S.

8x-16=-20 is correct .

7 0
3 years ago
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