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Nady [450]
3 years ago
12

(t-4)(3t+1)(t+2)=0 hats the answer

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0
(3t² +t -12t - 4)(t+2)=0
(3t³ - 5t² -26t -8) =0
t = -2
Rasek [7]3 years ago
3 0
T equals -2 hope this helps
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The general term for the sequence 2, 4, 8, 16, 32, . . . is
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We are given

sequence is 2 , 4 , 8 ,16 , 32 , .....

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We will find common ratio between successive terms

and then we check whether they are equal

r1=(second term)/(first term)

r_1=\frac{4}{2}=2

r2=(third term)/(second term)

r_2=\frac{8}{4}=2

r3=(fourth term)/(third term)

r_3=\frac{16}{8}=2

r4=(fifth term)/(fourth term)

r_4=\frac{32}{16}=2

we can see that all four ratios are same

r_1=r_2=r_3=r_4=2

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Calculation of general term:

We got

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Let's assume

number of terms is n

first term is 2

a_1=2

now, we can use formula

a_n=a_1 (r)^{n-1}

we can plug values

and we get

a_n=2(2)^{n-1}

a_n=2^1(2)^{n-1}

a_n=(2)^{n-1+1}

a_n=(2)^{n}..................Answer


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