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2 years ago

A baker uses 1/2 cup of sugar to make 7/8 of a batch of brownies. How many

Mathematics

1 answer:

Verizon [17]2 years ago

8 0

Answer:

5/8 of a cup

Step-by-step explanation:

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Consider the equation 2x+8y=12

rusak2 [61]

For a you have to solve 2 solutions , first 2x=12
6=x then you plug that back in, 12+8y=12
8y=0
y=0
(6,0)

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2 years ago

If f(x) = −3x + 4 and g(x) = 2, solve for the value of x for which f(x) = g(x) is true.

Komok [63]

<u>Answer</u>

2/3

<u>Explanation</u>

For f(x) = g(x) we should equate the two functions to get the value of x.

f(x) = g(x)

−3x + 4 = 2

-3x + 4 - 4 = 2 - 4

-3x = -2

Dividing by -3 on both sides;

(-3x)/-3 = (-2)/-3

x = 2/3

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2 years ago

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It is not possible to calculate the theoretical probability of making a basketball shot, because there are too many factors invo

sladkih [1.3K]

Answer:

Step-by-step explanation:

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2 years ago

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Suppose that x is a binomial random variable with n=5, p=. 3,and q=. 7.1. Write the binomial formula for this situation and list

Radda [10]

Answer:

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: Any from 0 to 5.

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 5, p = 0.3, q = 1 - p = 0.7$

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: 5 trials, so any value from 0 to 5.

For each value of x calculate p(☓ =x)

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

8 0

3 years ago

Given that J is between H and K. If JK=3x-1, HJ=2x+4, and HK=12, find x and JK.

cricket20 [7]

Answer:

X=7

Step-by-step explanation:

HJ + JK = HK

3(X + 2) +(3X - 4) = 44

3X + 6 + 3X - 4 = 44

6X + 2 = 44

6X = 42

X = 7

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3 years ago

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