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andrey2020 [161]
3 years ago
7

Brian just bought a pizza. He wants to share it with his friends. If he gave Myasia 1/8 of the pizza and gave damian 2/3. How mu

ch pizza does he have leftover for himself?
Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

o or 7 cause there a mistake you put 1/8 and it should be 7 and then you put 2/3 again...

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[(8*9)] - (6*7)] -15
maks197457 [2]

Answer:

15

Step-by-step explanation:

Simplify the following:

8×9 - 6×7 - 15

8×9 = 72:

72 - 6×7 - 15

-6×7 = -42:

72 + -42 - 15

72 - 42 - 15 = 72 - (42 + 15):

72 - (42 + 15)

| 4 | 2

+ | 1 | 5

| 5 | 7:

72 - 57

| 6 | 12

| 7 | 2

- | 5 | 7

| 1 | 5:

Answer:  15

3 0
3 years ago
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Only 17 and 18 plz it's math least to greatest
PilotLPTM [1.2K]
17) from least to greatest

1/8, 1/4, 3/8, 1/2, 5/8, 3/4, 7/8, 1
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3 years ago
3. [6x - 2y=2.<br> (2 + 6x=y
Hunter-Best [27]

Answer:

3. [6x - 2y=2.

(2 + 6x=y

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

6 0
3 years ago
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