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andrew-mc [135]
3 years ago
13

Mike did so well with his bike sale, he's going to Discount his helmets 15% off. If the Sale Price is $23.80, find the ORIGINAL

PRICE of a helmet.
Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0

Answer:

$3.57

Step-by-step explanation:

Multiply $23.80 by %15

Change %15 to a decimal by multiplying it by 100.

0.15 x $23.80= $3.57

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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
3 years ago
A cone has a height of 17 centimeters. What is its volume? Use n 3.14
skad [1K]

Answer:

444.83

Step-by-step explanation:

volume of a cone is given by the formula pi × r^2 × h × 1/3

by implementing the formula we get the answer which is 444.83

make sure to ask if you need any further guidance :)

8 0
2 years ago
Given the quadratic equation ax²-5b+4a=0, where a and b are constants has two real an equal roots,find a:b​
sergiy2304 [10]

Answer:

Therefore either a:b = 5:4 or a:b=-5:4

Step-by-step explanation:

ax²-5bx+4a=0

Since the quadratic equation has two real root.

Then b²-4ac>0

Here a= a , b= -5b and c=4a

∴(-5b)²-4.a.4a=0

⇔25b²=16a²

⇔5b=±4a

\Leftrightarrow \frac{a}{b} =\pm\frac{5}{4}

Therefore either a:b = 5:4 or a:b=-5:4

5 0
3 years ago
Please help me with this!! ( links= report )
artcher [175]

Answer:

Step-by-step explanation:

parrelograpm (b*H)

40cm^2

Area of semi circle 1/2(pi)r^2

1/2(pi)(5)^2

39.26990

total?

40+39.26990=79.26990

4 0
3 years ago
Find the magnitude of the vector (3, -6).Write your answer in simplified radical form.0/0 (0,0)X Х5?
bekas [8.4K]
\begin{gathered} \vec{}v=\text{ (x,y)} \\ \lvert v\rvert=\sqrt[]{x^2+y^2\text{ }}\text{ this is the magnitud of a vector} \\ \text{the radical form is when you expess a number with his roots.} \\ \lvert v\rvert=\sqrt[]{3^2+(-6)^2} \\ \lvert v\rvert=\sqrt[]{9^{}+36} \\ \lvert v\rvert=\sqrt[]{45}\text{ but by law of the radicals can be simplified as follows } \\ \lvert v\rvert=\sqrt[]{5\cdot9}\text{ } \\ \lvert v\rvert=\sqrt[]{5^{}}\text{ }\sqrt[]{9}\text{ = 3 }\sqrt[]{5} \end{gathered}

8 0
1 year ago
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