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3 years ago

Factorise fully 9x+15

Mathematics

1 answer:

sammy [17]3 years ago

6 0

Answer:

3(3x + 5)

Step-by-step explanation:

9x + 15

find a common factor, 3

3(3x + 5), this is the answer as u can't factorize anymore

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Please help thank you

allochka39001 [22]

I think it's 20. Sorry if it's wrong

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3 years ago

Evaluate the determinant for the following matrix [3 -5 / 1 1]

Natalka [10]

Answer:

Step-by-step explanation:

$\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2$

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3 years ago

Please help math thank you

Alina [70]

a: 30

b:40

c:78

d:36

e:20

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4 years ago

Read 2 more answers

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

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3 years ago

Write the following fractions in word. 3/4, 1/5, 3/4, 1 3/5.. please help me

Alik [6]

Answer:

"In word" as in word form?

3/4 = three fourths

1/5 = one fifth

3/4 = three fourths (again?)

1 3/5 = one and three fifths

4 0

3 years ago