Answer:
The answer to your question is: ∠K = 138°
Step-by-step explanation:
m∠N = 42°
m∠K = ?
The sum of all the internal angles in a quadrangle equals 360°
then
∠N + ∠L + ∠M + ∠K = 360°
∠N = ∠ L and ∠M = ∠K
So, 2 ∠N + 2 ∠K = 360
Substitution
2 (42) + 2 ∠K = 360
84 + 2 ∠K = 360
2 ∠K = 360 - 84
2 ∠K = 276
∠K = 276 / 2
∠K = 138°
Answer:
Step-by-step explanation:
The given data is 11, 77, 35, 5, 76, 34, 89, 92, 22
The total number of items in the data is 9. The width of each class interval would be gotten by dividing the difference between the minimum and maximum items in the data by the number of class intervals. From the information given,
Minimum item = 5
Maximum item = 92
Difference = 92 - 5 = 7
Class width = 87/10 = 8.7
By approximation, it is closest to 10
Therefore, the appropriate class group is 0 to 10
Input is 4.
Process machine:
Input > - 7 > ÷ 3 > Output
Solve:
(Input) 4 - 7 = <u>-3</u>
<u>-3</u> ÷ 3 = <u>-1 </u>(Output)
Input = 4
Output = -1
It depends if its decreasing 25% of the original quantity or decreasing by 25% of the quanity that is after already increasing by 25%.
Answer:
Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data.
Is there any more details, I could give a better answer.
