Answer:
BC < ED ⇒ answer A
Step-by-step explanation:
* Lets revise some facts in the triangle
- If one side of a triangle is longer than another side, then the angle
opposite the longer side will be larger than the angle opposite the
shorter side
- If one angle in a triangle is larger than another angle in a triangle,
then the side opposite the larger angle will be longer than the side
opposite the smaller angle
* Lets solve the problem
- In the two triangles BCD and DEB
∵ CD = 8 and BE = 8
∴ CD = BE
∵ Side BD is a common side in the two triangles
- The third side in Δ BCD is BC and the third side in DEB is DE
∵ BC is the opposite side to the angle of measure 24°
∵ ED is the opposite side to the angle of measure 30°
∵ The measure 24° < the measure 30°
∴ The side opposite to the angle of measure 24° < the side opposite
to the angle of measure 30°
∵ The other two sides of the 2 triangles BCD and DEB are equal
∴ We can compare between the 3rd sides in the Δ BCD and Δ DEB
∴ BC < ED
A chord and a radius form an equilateral triangle.
The area of the larger segment is:
A = 5/6 r² π + r²√3/2 = 5/6 · 64 · 3.14 + 32 · 1.73 =
= 167.47 + 55.36 = 222.83 in²
A = Lw
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1/2 = (2/3)w
w = (1/2)(3/2)
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w = 3/4 yard
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Hello im Nora :)))) okay hi hello oops
2n-9-5-8n+4n
= 2n-14-4n
=2n-14
