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3 years ago

A ship sails on a bearing of 020° for 30 km.

Mathematics

1 answer:

zepelin [54]3 years ago

7 0

Answer:

The ship travels approximately 10.261 meters to the East.

Step-by-step explanation:

At first we introduce a graphical description of the statement as an attachment below. Let suppose that bearing is respect to the North-direction, then the change in position in the East direction is modelled by the following Trigonometric formula:

$x = r\cdot \sin \theta$ (1)

Where:

$r$ - Distance travelled by the ship, measured in kilometers.

$\theta$ - Bearing angle, measured in sexagesimal degrees.

$x$ - Distance component in the east direction, measured in kilometers.

If we know that $r = 30\,km$ and $\theta = 20^{\circ}$ , then the distance in the East direction is:

$x = (30\,km)\cdot \sin 20^{\circ}$

$x \approx 10.261\,m$

The ship travels approximately 10.261 meters to the East.

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The residual plot for a data set is shown.

Cerrena [4.2K]

Answer:

The regression line is not a good model because there is a pattern in the residual plot.

Step-by-step explanation:

Given is a residual plot for a data set

The residual plot shows scatter plot of x and y

The plotting of points show that there is not likely to be a linear trend of relation between the two variables. It is more likely to be parabolic or exponential.

Hence the regression line cannot be a good model as they do not approach 0.

Also there is not a pattern of linear trend.

D) The regression line is not a good model because there is a pattern in the residual plot.

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3 years ago

Read 2 more answers

In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s

Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 210, \sigma = 38.6$