Question

A ship sails on a bearing of 020° for 30 km.

Answer 1

Answer:

The ship travels approximately 10.261 meters to the East.

Step-by-step explanation:

At first we introduce a graphical description of the statement as an attachment below. Let suppose that bearing is respect to the North-direction, then the change in position in the East direction is modelled by the following Trigonometric formula:

$x = r\cdot \sin \theta$ (1)

Where:

$r$ - Distance travelled by the ship, measured in kilometers.

$\theta$ - Bearing angle, measured in sexagesimal degrees.

$x$ - Distance component in the east direction, measured in kilometers.

If we know that $r = 30\,km$ and $\theta = 20^{\circ}$, then the distance in the East direction is:

$x = (30\,km)\cdot \sin 20^{\circ}$

$x \approx 10.261\,m$

The ship travels approximately 10.261 meters to the East.