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deff fn [24]
2 years ago
11

Pls help asap! i will mark brainliest!

Mathematics
1 answer:
Nastasia [14]2 years ago
7 0

Answer:

hj

Step-by-step explanation:

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Anyone help me solve for y.
riadik2000 [5.3K]

Answer:

y = - 4

Step-by-step explanation:

Given

y = 2x + ( - 2) , that is

y = 2x - 2 ← substitute x = - 1

y = 2(- 1) - 2 = - 2 - 2 = - 4

This is confirmed by the point (- 1, - 4 ) on the graph

3 0
3 years ago
Read 2 more answers
jesse is putting a ribbon around a square frame. He uses 24 inches of ribbon. How long is each side of the frame
OverLord2011 [107]
Answer
24÷4=6
So six
7 0
3 years ago
Determine whether each pair of segments is congruent
Dafna1 [17]

They are both labeled as 3 feet, so both must be equal, unless you doubt the labeling. Unless that is so, then both segments are equal.

6 0
4 years ago
Please help me with this
Masja [62]

Answer:

c = a - 16

Step-by-step explanation:

Given

a = b + 12 ( subtract 12 from both sides )

a - 12 = b

Substitute b = a - 12 into b = c + 4

a - 12 = c + 4 ( add 12 to both sides )

a = c + 16  ( subtract 16 from both sides )

c = a - 16

5 0
2 years ago
Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
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